Tolong dong, ada yg bisa jawab gak??
f(x) = y
[tex] \frac{6x + 3}{4} = y[/tex]
6x + 3 = 4y
6x = 4y - 3
[tex]x = \frac{4y - 3}{6} \\ f {}^{ - 1} (x) = \frac{4x - 3}{6} [/tex]
[answer.2.content]
f(x) = y
[tex] \frac{6x + 3}{4} = y[/tex]
6x + 3 = 4y
6x = 4y - 3
[tex]x = \frac{4y - 3}{6} \\ f {}^{ - 1} (x) = \frac{4x - 3}{6} [/tex]
[answer.2.content]